but remember, the camera needs to be connected and running to make this measurement.
iHerve, You have to measure the voltage with connected camera !
You have two resistors in a chain - the cable and the camera. At both, you have a drop, which is proportional to their resistance.
Using Jeffs formula:
E = I • R (E is voltage, I is current, R is resistance)
E = 0.5 • 1.32
E = 0.66 Volts
Form Jeff's first fomula to "I = E / R".
When the amperage is I, so it is the same amperage in the camera and in the cable. So
"E = I • (R Cable + R Camera)"
and
"I = E Camera / R Camera = E Cable / R Cable" or better: "E Camera / R Camera = E Cable / R Cable"
->
E Camera / R Camera * R Cable = E Cable
When no camera is connected, the missing "Camera resistor" goes to endless. Camera's drop (can be 0 V to max 12 V, but however) devided by endless is zero (multiplicatad by 1,32 is also zero).
So, without camera, you measure full 12V voltage (E camera) at at the end of the cable - a drop near zero in the cable (E Cable)....
With a "real" Camera wich has a "normal" value for resistance you get a drop like described by Jeff.
I hope my english an my mathematics were good enough for understanding